Line slope calculator 8x+y=58
Straight line given by points A[6; 10] and B[7; 2]
Calculation:
Slope: m = -8Slope-intercept form of line: y = -8x+58
Canonical form of the line equation: 8x+y-58 = 0
Parametric form of the line equation:
x = t+6
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -82°52'30″ = -1.4464 rad
X intercept: x0 = 7.25
Y intercept: y0 = q = 58
Distance line from the origin: d0 = 7.194
The length of the segment AB: |AB| = 8.0623
Vector: AB = (1; -8)
Normal vector: n = (8; 1)
Midpoint of the segment AB: M = [6.5; 6]
Perpendicular Bisector equation: x-8y+41.5 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (7; 2) ; |OB| = 7.2801
Scalar product OA .OB = 62
Angle ∠ AOB = 43°5'27″ = 0.7521 rad