Line slope calculator 4x+y=38
Straight line given by points A[7; 10] and B[8; 6]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+38
Canonical form of the line equation: 4x+y-38 = 0
Parametric form of the line equation:
x = t+7
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 9.5
Y intercept: y0 = q = 38
Distance line from the origin: d0 = 9.2164
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [7.5; 8]
Perpendicular Bisector equation: x-4y+24.5 = 0
Vector OA = (7; 10) ; |OA| = 12.2066
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 116
Angle ∠ AOB = 18°8'17″ = 0.3166 rad