# Parabola

Find the equation of a parabola that contains the points at A[-8; -6], B[-1; -9], C[8; -6]. (use y = ax2+bx+c)

Result

a =  0.048
b =  0
c =  -9.048

#### Solution:

a*(-8)^2 + b*(-8) + c = -6
a*(-1)^2 + b*(-1) + c = -9
a*(8)^2 + b*(8) + c = -6

64a-8b+c = -6
a-b+c = -9
64a+8b+c = -6

a = 1/21 ≈ 0.047619
b = 0
c = -190/21 ≈ -9.047619

Calculated by our linear equations calculator.

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