Semicircle

The semicircle with center S and the diameter AB is constructed equilateral triangle SBC.

What is the magnitude of the angle ∠SAC?

Correct answer:

SAC =  30 °

Step-by-step explanation:

SBC=SCB = BCS SCB=180/3=60  ACB=90   SAC=SAC=ACBSCB=9060=30



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