Trains

From station 130 km away started passenger train and after 1.9 hours after the express train, which travels 27 km an hour more. Express train finish journey 5 minutes early.

Calculate the average speed of these two trains.

Correct answer:

v1 =  192.2 km/h
v2 =  219.2 km/h

Step-by-step explanation:

v1t1=v2t2=130 v2=v1+27 t2=t15/60  v1t1=130 v1t10.083v1+27t1270.083=130  t1=0.003v1+0.083  v1(0.003v1+0.083)=130  0.0030864197530864x2+0.083x130=0  a=0.003086;b=0.083;c=130 D=b24ac=0.083240.003086(130)=1.611882716 D>0  x1,2=2ab±D=0.0061730.08±1.61 x1,2=13.5±205.675108 x1=192.175107876 x2=219.175107876   Factored form of the equation:  0.0030864197530864(x192.175107876)(x+219.175107876)=0  v1=192.2 km/h
v2=v1+27=219.2 km/h



Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Do you have a linear equation or system of equations and looking for its solution? Or do you have a quadratic equation?
Do you want to convert length units?
Do you want to convert velocity (speed) units?
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: