# Tram

In the three-part tram went 206 passengers in front of others, 226 after others and in the middle half of all.

How many passengers went in tram total?

Result

x =  288

#### Solution:

a+b=206
b+c=226
b = 1/2*(a+b+c)
x=a+b+c

a+b = 206
b+c = 226
a-b+c = 0
a+b+c-x = 0

a = 62
b = 144
c = 82
x = 288

Calculated by our linear equations calculator.

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