# Pyramid a+h

Calculate the volume and surface area of the pyramid on the edge and height a = 26 cm. h = 3 dm.

Correct result:

S =  2376.169 cm2
V =  6760 cm3

#### Solution:

$a=26 \ \text{cm} \ \\ v=3 \cdot \ 10=30 \ \text{cm} \ \\ S_{1}=a^2=26^2=676 \ \text{cm}^2 \ \\ h_{2}=\sqrt{ v^2 + (a/2)^2 }=\sqrt{ 30^2 + (26/2)^2 } \doteq \sqrt{ 1069 } \ \text{cm} \doteq 32.6956 \ \text{cm} \ \\ S_{2}=a \cdot \ h_{2}/2=26 \cdot \ 32.6956/2 \doteq 13 \ \sqrt{ 1069 } \ \text{cm}^2 \doteq 425.0424 \ \text{cm}^2 \ \\ S=S_{1}+4 \cdot \ S_{2}=676+4 \cdot \ 425.0424=2376.169 \ \text{cm}^2$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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