Container with water

The weight of a container with water is 2.48 kg. Suppose the cast is 75% water, and the container with water weighs 0.98 kg. Determine the weight of the empty container. How much water was originally in the container?

Correct answer:

m =  0.48 kg
v =  2 kg

Step-by-step explanation:


m + v = 2.48
m+(1-75/100)·v = 0.98

m+v = 2.48
100m+25v = 98

Pivot: Row 1 ↔ Row 2
100m+25v = 98
m+v = 2.48

Row 2 - 1/100 · Row 1 → Row 2
100m+25v = 98
0.75v = 1.5


v = 1.5/0.75 = 2
m = 98-25v/100 = 98-25 · 2/100 = 0.48

m = 12/25 = 0.48
v = 2

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