Journey to school

On the way to school I went steady step. In the first half of the journey, I counted every second step, in the second half every third. How many steps I do when I went to school if I counted double step are 250 more than three steps?

Result

n =  3000

Solution:


a = 250 + b
x = 2a + 3b
2a = 3b

a-b = 250
2a+3b-x = 0
2a-3b = 0

a = 750
b = 500
x = 3000

Calculated by our linear equations calculator.







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To solve this example are needed these knowledge from mathematics:

Do you have a linear equation or system of equations and looking for its solution? Or do you have quadratic equation?

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