Hiker and cyclist

At 7 PM hiker started at 6 km/h to hike. After three hrs. later started on the same trip cyclist at a speed of 15 km/h. After an hour of driving a flat tire and takes him half hour to correct the defect. At what time catch up cyclist with the hiker?

Result

t = 12:50 h Wrong answer

Step-by-step explanation:


6(t-7.00) = 15(t-(7.00+3.00+0.5))

6·(t-7.00) = 15·(t-(7.00+3.00+0.5))

9t = 115.5


t = 115.5/9 = 12.83333333

t = 77/6 ≈ 12.833333

Our simple equation calculator calculates it.



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