Three ints

The sum of three consecutive integers is 2016. What numbers are they?

Correct answer:

a =  671
b =  672
c =  673

Step-by-step explanation:


a+b+c=2016
b = a+1
c = b+1

a+b+c = 2016
a-b = -1
b-c = -1

Row 2 - Row 1 → Row 2
a+b+c = 2016
-2b-c = -2017
b-c = -1

Row 3 - 1/-2 · Row 2 → Row 3
a+b+c = 2016
-2b-c = -2017
-1.5c = -1009.5


c = -1009.5/-1.5 = 673
b = -2017+c/-2 = -2017+673/-2 = 672
a = 2016-b-c = 2016-672-673 = 671

a = 671
b = 672
c = 673

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