Determine 2796

Find the first ten members of the sequence if a11 = 132, d = 7.

Correct answer:

a10 =  125
a9 =  118
a8 =  111
a7 =  104
a6 =  97
a5 =  90
a4 =  83
a3 =  76
a2 =  69
a1 =  62

Step-by-step explanation:

a10=1327=125
a9=1257=118
a8=1187=111
a7=1117=104
a6=1047=97
a5=977=90
a4=907=83
a3=837=76
a2=767=69
a1=697=62



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