Motel

Three different dinners A, B, C are served in the motel.
Three 20 members went to motel. Group 1 ordered dinners: A 20 members and their average dinner price in the group was CZK 200. From Group 2, they ordered a A: 10 persons, B 10 dinners, and their average dinner dinner price for the group was 240 CZK. From Group 3, they ordered a 5 persons A dinners, B 5 dinners, a C 10 dinners, and their average dinner price was CZK 270.
Calculate the price of dinner A, B, C.

Result

A =  200
B =  280
C =  300

Solution:


20A=20*200
10A +10B = 20*240
5A+5B+10C = 20*270

20A = 4000
10A+10B = 4800
5A+5B+10C = 5400

A = 200
B = 280
C = 300

Calculated by our linear equations calculator.








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