Internal angles

Find the internal angles of the triangle ABC if the angle at the vertex C is twice the angle at the B and the angle at the vertex B is 4 degrees smaller than the angle at vertex A.

Correct answer:

A =  48
B =  44
C =  88

Step-by-step explanation:


A+B+C=180
C = 2·B
B = A-4

A+B+C = 180
2B-C = 0
A-B = 4

Row 3 - Row 1 → Row 3
A+B+C = 180
2B-C = 0
-2B-C = -176

Row 3 + Row 2 → Row 3
A+B+C = 180
2B-C = 0
-2C = -176


C = -176/-2 = 88
B = 0+C/2 = 0+88/2 = 44
A = 180-B-C = 180-44-88 = 48

A = 48
B = 44
C = 88

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