How many elements can form six times more combinations fourth class than combination of the second class?
Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):
Showing 0 comments:
Be the first to comment!
To solve this example are needed these knowledge from mathematics:
Next similar examples:
- 2nd class combinations
From how many elements you can create 4560 combinations of the second class?
From how many elements we can create 990 combinations 2nd class without repeating?
- Fish tank
A fish tank at a pet store has 8 zebra fish. In how many different ways can George choose 2 zebra fish to buy?
How many different triads can be selected from the group 38 students?
- The confectionery
The confectionery sold 5 kinds of ice cream. In how many ways can I buy 3 kinds if order of ice creams does not matter?
How many ways can divide 16 players into two teams of 8 member?
Division has 18 members: 10 girls and 6 boys, 2 leaders. How many different patrols can be created, if one patrol is 2 boys, 3 girls and 1 leader?
How many 4-tones chords (chord = at the same time sounding different tones) is possible to play within 7 tones?
- Variations 4/2
Determine the number of items when the count of variations of fourth class without repeating is 600 times larger than the count of variations of second class without repetition.
Equation ? has one root x1 = 8. Determine the coefficient b and the second root x2.
Determine the quadratic equation absolute coefficient q, that the equation has a real double root and the root x calculate: ?
- Quadratic equation
Find the roots of the quadratic equation: 3x2-4x + (-4) = 0.
Determine the discriminant of the equation: ?
- Quadratic function 2
Which of the points belong function f:y= 2x2- 3x + 1 : A(-2, 15) B (3,10) C (1,4)
- Calculation of CN
The player gets 8 cards of 32. What is the probability that it gets a) all 4 aces b) at least 1 ace
- Theorem prove
We want to prove the sentense: If the natural number n is divisible by six, then n is divisible by three. From what assumption we started?