# Pool

The swimming pool is 10 m wide and 8 m long and 153 cm deep. How many hectoliters of water is in it, if the water is 30 cm below its upper edge?

Correct result:

V =  984 hl

#### Solution:

$a=10 \ \text{m} \ \\ b=8 \ \text{m} \ \\ c_{1}=153-30=123 \ \text{cm} \ \\ \ \\ c=c_{1} \rightarrow m=c_{1} / 100 \ m=123 / 100 \ m=1.23 \ m \ \\ V_{1}=a \cdot \ b \cdot \ c=10 \cdot \ 8 \cdot \ 1.23=\dfrac{ 492 }{ 5 }=98.4 \ \text{m}^3 \ \\ V=V_{1} \rightarrow hl=V_{1} \cdot \ 10 \ hl=98.4 \cdot \ 10 \ hl=984 \ hl=984 \ \text{hl}$

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Math student
IT'S 9 CM NOT 10 CM. SO IT SHOULD BE 4004.

Dr Math
corrected, thank you

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