Pyramid roof

1/3 of the area of ​​the roof-shaped regular tetrahedral pyramid with base edge 8 m and height of 4 m is already covered with roofing. How many square meters still need to be covered?

Correct answer:

S =  60.3398 m2

Step-by-step explanation:

a=8 m h=4 m  q=11/3=320.6667  h1=h2+(a/2)2=42+(8/2)2=4 2 m5.6569 m  S1=2a h1=28 5.6569=16 2 m222.6274 m2  S=q 4 S1=0.6667 4 22.6274=60.3398 m2



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