Movement

From the crossing of two perpendicular roads started two cyclists (each on a different road). One runs at an average speed of 28 km/h, and the second 24 km/h. Determine the distance between them after 45 minutes of cycling.

Correct answer:

x =  27.6586 km

Step-by-step explanation:

t=45 min h=45:60  h=0.75 h v1=28 km/h v2=24 km/h  s1=v1 t=28 0.75=21 km s2=v2 t=24 0.75=18 km  x=s12+s22=212+182=3 85=27.6586 km



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