Motion

Cyclist started at 9:00 from point S to point T. After 10 minutes, followed him at the same speed the second cyclist. Walker, which went from T to S, started at 9:35. After 71 minutes he met the first cyclist and after next 8 minutes the second cyclist.
Distance between the two cities is 37 km.

Determine the (same) speed of cyclists and walker.

Correct result:

v1 =  17.9 km/h
v2 =  4.5 km/h

Solution:

37=v135+7160+v27160 37=v135+71+81060+v271+860  2220=106v1+71v2 2220=104v1+79v2  v1=17.9 km/h
v2=4.5 km/h



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