Motion

If you go at speed 5.5 km/h, you come to the station 33 minutes after leaving the train. If you bike to the station at speed 29 km/h, you come to the station 52 minutes before its departure.
How far is the train station?

Correct answer:

s =  9.6152 km

Step-by-step explanation:

v1=5.5 km/h v2=29 km/h t1 = (x + 33)/60  h t2 = (x  52)/60  h s = v1   t1 = v2   t2 v1( x+ 33 ) = v2( x  52 ) x=v2v1v1 33+v2 52=295.55.5 33+29 52=47337971.8936 min t1=(x+33)/60=(71.8936+33)/60=2824931.7482 h t2=(x52)/60=(71.893652)/60=5641870.3316 h  s = s1 = s2 s1=v1 t1=5.5 1.7482=56454239.6152 km s=v2 t2=29 0.3316=9.6152 km



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