Equation of circle 2

Find the equation of a circle that touches the axis of y at a distance of 4 from the origin and cuts off an intercept of length 6 on the axis x.

Result

f : (Correct answer is: ) OK

Step-by-step explanation:

A = (0,4) B = (x0+6/2,0) C = (x06/2,0)  (xx0)2 + (yy0)2 = r2  (0x0)2 + (4y0)2 = r2 (x0+3x0)2 + (0y0)2 = r2 (x03x0)2 + (0y0)2 = r2  x02 + (4y0)2 = r2 9 + y02 = r2 9 + y02 = r2  r=5 x0=5 y0=4  f=(x5)2+(y4)=52



Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Do you have a linear equation or system of equations and looking for its solution? Or do you have a quadratic equation?
See also our right triangle calculator.
See also our trigonometric triangle calculator.

 
We encourage you to watch this tutorial video on this math problem: video1   video2

Related math problems and questions: