# Evaluation of expressions

If a

(i)a

(ii) a

^{2}-3a+1=0, find(i)a

^{2}+1/a^{2}(ii) a

^{3}+1/a^{3}**Result****Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):**

**Showing 0 comments:**

**Be the first to comment!**

#### To solve this example are needed these knowledge from mathematics:

## Next similar examples:

- Algebra

X+y=5, find xy (find the product of x and y if x+y = 5) - Expression with powers

If x-1/x=5, find the value of x^{4}+1/x^{4} - Quadratic equation

Find the roots of the quadratic equation: 3x^{2}-4x + (-4) = 0. - Square root 2

If the square root of 3m^{2}+22 and -x = 0, and x=7, what is m? - Solve equation

solve equation: ? - Difference AP 4

Calculate the difference of the AP if a1 = 0.5, a2 + a3 = -1.1 - Crystal water

The chemist wanted to check the content of water of crystallization of chromic potassium alum K_{2}SO_{4}* Cr_{2}(SO_{4}) 3 * 24 H_{2}O, which was a long time in the laboratory. From 96.8 g of K_{2}SO_{4}* Cr_{2}(SO_{4}) 3 * 24 H_{2}O prepared 979 cm^{3}solution of base. S - Equation

Equation ? has one root x_{1}= 8. Determine the coefficient b and the second root x_{2}. - Solve 3

Solve quadratic equation: (6n+1) (4n-1) = 3n^{2} - Roots

Determine the quadratic equation absolute coefficient q, that the equation has a real double root and the root x calculate: ? - Discriminant

Determine the discriminant of the equation: ? - Quadratic equation

Quadratic equation ? has roots x_{1}= 80 and x_{2}= 78. Calculate the coefficients b and c. - Variation equation

Solve combinatorics equation: V(2, x+8)=72 - Equation with abs value

How many solutions has the equation ? in the real numbers? - Tubes

Iron tubes in the warehouse are stored in layers so that each tube top layer fit into the gaps of the lower layer. How many layers are needed to deposit 100 tubes if top layer has 9 tubes? How many tubes are in bottom layer of tubes? - Reciprocal equation 2

Solve this equation: x + 5/x - 6 = 4/11 - Theorem prove

We want to prove the sentense: If the natural number n is divisible by six, then n is divisible by three. From what assumption we started?