Digit sum

How many are three-digit numbers that have a digit sum of 6?

Correct answer:

n =  21

Step-by-step explanation:

6 = a+b+c a>0 b0 c0  n1 = 105 n2 = 114 n3 = 123 n4 = 132 n5 = 141 n6 = 150 n7 = 204 n8 = 213 n9 = 222 n10 = 231 n11 = 240 n12 = 303 n13 = 312 n14 = 321 n15 = 330 n16 = 402 n17 = 411 n18 = 420 n19 = 501 n20 = 510 n21 = 600  n=21



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