Monty Hall

Suppose you're on a game show and have the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat.

What is the probability that the chosen door is open and you will see them in the car?

What is the probability that you will change your decision, open the remaining doors, and see the car?

Correct answer:

p1 =  33.3 %
p2 =  66.7 %
result if staying at door :  0 1

Step-by-step explanation:

behind door 1 behind door 2 behind door 3 result if staying at door #1 result if switching to the door offered
car goat goat car goat
goat car goat goat car
goat goat car goat car

p2=2/3 100=66.7%



Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Would you like to compute the count of combinations?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: