Cyclist who rides at an average speed 16 km/h travels trip distance 10 min before the cyclist who rides at an average speed 11 km/h.

What is the length of this cyclist trip(distance in km)?


s =  5.87 km


Solution in text s =

s = 11 t

300t = 160
s-11t = 0

s = 8815 ≈ 5.866667
t = 815 ≈ 0.533333

Calculated by our linear equations calculator.

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