Practice problems of the volume of a prism - page 3 of 20
Number of problems found: 385
- Cross-section 8171
How many m³ of soil is to be excavated when digging a 120 m long ditch, the cross-section of which is an isosceles trapezoid with bases of 2.3 m and 3.3 m, if the depth of the trench is 90 cm? - Octagonal prism vase
We can pour 0.7 l of water into an octagonal prism vase. The vase has the bottom has an area of 25 cm square and a thickness of 12 mm. What is the height of the vase? - Cross-section 79984
A ditch with a cross-section in the shape of an isosceles trapezoid with bases of 3 m and 5 m and arms of length 2 m is 2.5 meters deep and 10 meters long. How many cubic meters of soil did they have to excavate when digging it? - Right-angled 6034
A three-sided prism has a base in the shape of a right-angled triangle with a length of 5 cm. The giant wall of the prism shell has a volume of 104 cm². The prism is 8 cm high. Calculate the volume and surface area of the prism. - Cross-section 5048
A path will lead to an embankment across the floodplain. The embankment will be 2 km long and have the shape of an isosceles trapezoid in cross-section with base lengths of 12 m and 8 m and a height of 2 m. Calculate the volume of material needed to build - Trapezoidal 4031
The aquarium has the shape of a prism with a trapezoidal base. The length of the basic trapezoid is 60 cm and 80 cm, and the height of the trapezoid is 70 cm. The aquarium holds 196 liters of water. How tall is the aquarium? - Calculate 23411
The prism with a diamond base has one base diagonal of 20 cm and a base edge of 26 cm. The edge of the base is 2:3 to the height of the prism. Calculate the volume of the prism. - Cross-section 4507
How much soil needs to be removed when digging a 200-meter long ditch whose cross-section is an isosceles trapezoid with an area of 4812.5 cm²? - Perpendicular prism network
Find the volume and surface of a triangular prism with the base of a right triangle, the network of which is 4 cm 3 cm (perpendiculars) and nine centimeters (height of the prism). - Hexagonal prism
The prism's base is a regular hexagon consisting of six triangles with side a = 12 cm and height va = 10.4 cm. The prism height is 5 cm. Find the volume and surface of the prism. - Prism
The base of a vertical triangular prism is a right triangle with legs 4.5 cm and 6 cm long. What is the surface of the prism if its volume is 54 cubic centimeters? - Prism
The volume of a tetrahedral prism is 2.43 m³. The prism's base is a parallelogram with a side of 2,5dm and height ha = 18cm. Calculate the height of the prism. - Triangular prism
Calculate a triangular prism if it has a rectangular triangle base with a = 4cm and hypotenuse c = 50mm, and the height of the prism is 0.12 dm. - Decagon prism
A regular decagon of side a = 2 cm is the base of the perpendicular prism. The side walls are squares. Find the prism volume in cm³, round to two decimal places. - Fifty-meter 80722
Calculate how many hectoliters of water can fit in a fifty-meter sloped pool; if the smallest depth is 1.2 m and the largest depth is 3 m, the width of the pool is 20 m. - Prism - right isosceles
Find the volume and surface of a prism with a height of 120 mm, the base of which is a right isosceles triangle with a leg length of 5 cm. - Isosceles + prism
Calculate the volume of the perpendicular prism if its height is 17.5 cm and the base is an isosceles triangle with a base length of 5.8 cm and an arm's length of 3.7 cm - Triangular prism
The base of the perpendicular triangular prism is a right triangle with a leg length of 5 cm. The area of the largest sidewall of its surface is 130 cm², and the body's height is 10 cm. Calculate its volume. - Equilateral 82136
A three-sided prism with a base in the shape of an equilateral triangle has a volume of 370 dm³. What is the volume of its base if it is 50 cm high? - Diamond base
The prism with a diamond base has 24 cm and 20 cm long base diagonals. Calculate the height of a prism with a volume of 9.6 dm³ (cubic decimetres)
Do you have homework that you need help solving? Ask a question, and we will try to solve it.