# Seven numbers

Write seven 4-digit numbers that are divisible by 3 and at the same time by 4.

Correct result:

a1 =  1008
a2 =  1020
a3 =  1032
a4 =  1044
a5 =  1056
a6 =  1068
a7 =  1080

#### Solution:

${a}_{2}={a}_{1}+d=1008+12=1020$
${a}_{3}={a}_{2}+d=1020+12=1032$
${a}_{4}={a}_{3}+d=1032+12=1044$
${a}_{5}={a}_{4}+d=1044+12=1056$
${a}_{6}={a}_{5}+d=1056+12=1068$
${a}_{7}={a}_{6}+d=1068+12=1080$

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