The sum

The sum of the first ten members of the arithmetic sequence is 120. What will be the sum if the difference is reduced by 2?

Correct answer:

s2 =  30

Step-by-step explanation:

s1=120 n=10  s1 = a1+a2+a3+ + an  d2 = d1  2  s1 = 10/2 (a1 + a1 + 9 d1) = 10 a1 + 45 d1 = 120 s2 = 10/2 [a1 + a1 + 9 (d12)] s2 = 10 a1 + 45 d1  5 9 2  s2=s15 9 2=1205 9 2=30



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