Three-day trip

The cyclist on three-day trip travel 30% of the total route on the first day, 3/5 of the rest on the second day and 35 km on the third day. How many kilometers did travel cyclists each day and how many?

Result

a =  37.5
b =  52.5
c =  35
s =  125

Solution:


a + b + c = s
a = 30/100 s
b = 3/5 * (s-a)
c = 35

a+b+c-s = 0
100a-30s = 0
3a+5b-3s = 0
c = 35

a = 752 = 37.5
b = 1052 = 52.5
c = 35
s = 125

Calculated by our linear equations calculator.

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