Coal mine

The towing wheel has a diameter of 1.7 meters. How many meters does the elevator cage lower when the wheel turns 32 times?

Result

l =  171 m

Solution:

D=1.7 m o=π D=3.1416 1.75.3407 m n=32  l=n o=32 5.3407170.9026=171  m D = 1.7 \ m \ \\ o = \pi \cdot \ D = 3.1416 \cdot \ 1.7 \doteq 5.3407 \ m \ \\ n = 32 \ \\ \ \\ l = n \cdot \ o = 32 \cdot \ 5.3407 \doteq 170.9026 = 171 \ \text { m }







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