# Year 2020

The four-digit number divided by 2020 gives a result of 1, **. (Can not be in form 1,*0. ) Write all the options.

Result

n1 =  2323
n2 =  2525
n3 =  2727
n4 =  2929
n5 =  3131
n6 =  3333
n7 =  3535
n8 =  3737
n9 =  3939

#### Solution:

$n_{ 1 } = 2323 \ \\ d_{ 1 } = n_{ 1 }/2020 = 2323/2020 = \dfrac{ 23 }{ 20 } = 1.15$
$n_{ 2 } = 2525 \ \\ d_{ 2 } = n_{ 2 }/2020 = 2525/2020 = \dfrac{ 5 }{ 4 } = 1.25$
$n_{ 3 } = 2727 \ \\ d_{ 3 } = n_{ 3 }/2020 = 2727/2020 = \dfrac{ 27 }{ 20 } = 1.35$
$n_{ 4 } = 2929 \ \\ d_{ 4 } = n_{ 4 }/2020 = 2929/2020 = \dfrac{ 29 }{ 20 } = 1.45$
$n_{ 5 } = 3131 \ \\ d_{ 5 } = n_{ 5 }/2020 = 3131/2020 = \dfrac{ 31 }{ 20 } = 1.55$
$n_{ 6 } = 3333 \ \\ d_{ 6 } = n_{ 6 }/2020 = 3333/2020 = \dfrac{ 33 }{ 20 } = 1.65$
$n_{ 7 } = 3535 \ \\ d_{ 7 } = n_{ 7 }/2020 = 3535/2020 = \dfrac{ 7 }{ 4 } = 1.75$
$n_{ 8 } = 3737 \ \\ d_{ 8 } = n_{ 8 }/2020 = 3737/2020 = \dfrac{ 37 }{ 20 } = 1.85$
$n_{ 9 } = 3939 \ \\ d_{ 9 } = n_{ 9 }/2020 = 3939/2020 = \dfrac{ 39 }{ 20 } = 1.95$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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