Isosceles IV

In an isosceles triangle ABC is |AC| = |BC| = 13 and |AB| = 10. Calculate the radius of the inscribed (r) and described (R) circle.

Correct result:

r =  3.33
R =  7.04

Solution:

h2=b2(c/2)2 h=13252=12 (bc/2)2+r2=(hr)2 82+r2=h22hr+r2 82=h22hr 82=122212r r=(12282)/(212)=3.33 
(c/2)2=h(2Rh)  R=c2/4+h22h R=52+122212 R=7.04

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