Alcohol

6l 48% alcohol, how much must we add 52% alcohol to give 50% alcohol?

Correct answer:

x =  6 l

Step-by-step explanation:

V=6 l p1=48%=10048=2512=0.48 p2=52%=10052=2513=0.52 p=50%=10050=21=0.5  V p1+x p2=p (x+V) 6 0.48+x 0.52=0.5 (x+6)  0.02x=0.12  x=0.020.12=6  x=6=6 l



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