Floating of wood - Archimedes law

Wooden balsa block has a density of 200 kg/m3 and a volume of 0.02 m3 floating in alcohol. Alcohol density is 789 kg/m3. What will be the volume of the floating part of a balsa block?

Correct answer:

V =  14930.2915 cm3

Step-by-step explanation:

ρ1=200 kg/m3 V1=0.02 m3 ρ2=789 kg/m3  m1 = m2 V ρ1 = (V1V) (ρ2ρ1) V ρ1 = V1 (ρ2ρ1)V (ρ2ρ1) V ρ2 = V1 (ρ2ρ1)  v=ρ2V1 (ρ2ρ1)=7890.02 (789200)0.0149 m3  V=v cm3=v 1000000  cm3=0.0149 1000000  cm3=14930.292 cm3=14930.2915 cm3



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