# Rectangular garden

The perimeter of Peter's rectangular garden is 98 meters. The width of the garden is 60% shorter than its length.
Find the dimensions of the rectangular garden in meters.
Find the garden area in square meters.

Result

a =  35 m
b =  14 m
S =  490 m2

#### Solution:

$o = 98 \ m \ \\ b = a - 0.60a \ \\ \ \\ o = 2(a+b) \ \\ \ \\ \ \\ o = 2 \cdot \ (a+(a - 0.60 \cdot \ a)) \ \\ \ \\ 98 = 2 \cdot \ (a+(a - 0.60 \cdot \ a)) \ \\ \ \\ 2.8a = 98 \ \\ \ \\ a = 35 \ \\ = 35 \ \text{ m }$
$b = a - 0.60a = 35 - 0.60 \cdot \ 35 = 14 = 14 \ \text{ m }$
$S = a \cdot \ b = 35 \cdot \ 14 = 490 = 490 \ m^2$

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