Crossroads

A passenger car and an ambulance come to the rectangular crossroad, and the ambulance leaves. Passenger car at speed 39 km/h and ambulance at 41 km/h.

Calculate the relative speed of the ambulance moving to the car.

Correct answer:

v =  56.59 km/h

Step-by-step explanation:

v1=39 km/h v2=41 km/h  s2 = s12 + s22 (vt)2 = (v1 t)2 + (v2 t)2  v2 = v12+v22  v=v12+v22=392+412=3202=56.59 km/h



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Math student
dont understand





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