# Crossroads

The rectangular crossroads comes passenger car and an ambulance, the ambulance left. Passenger car is at 36 km/h and ambulance 47 km/h.

Calculate such a relative speed of the ambulance moves to the car.

Result

v =  59.2 km/h

#### Solution:

$v_{ 1 } = 36 \ km/h \ \\ v_{ 2 } = 47 \ km/h \ \\ \ \\ v^2 = v_{ 1 }^2+v_{ 2 }^2 \ \\ \ \\ v = \sqrt{ v_{ 1 }^2+v_{ 2 }^2 } = \sqrt{ 36^2+47^2 } = \sqrt{ 3505 } \doteq 59.203 = 59.2 \ \text { km/h }$

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#### Following knowledge from mathematics are needed to solve this word math problem:

Two vectors given by its magnitudes and by included angle can be added by our vector sum calculator. Pythagorean theorem is the base for the right triangle calculator.

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