Box of chocolates

In a box of chocolates were 16 candies. Christopher and Luke were distributed:
a) Christopher had about four candies over Luke,
b) Christopher had about six candies less than Luke,
c) Christopher had three times more sweets than Luke. How many had each boy candies?

Correct answer:

a) k =  10
a) l =  6
b) K =  5
b) L =  11
c) x =  12
c) y =  4

Step-by-step explanation:


k+l=16
k=4+l

k+l = 16
k-l = 4

Row 2 - Row 1 → Row 2
k+l = 16
-2l = -12


l = -12/-2 = 6
k = 16-l = 16-6 = 10

k = 10
l = 6

Our linear equations calculator calculates it.

K+L=16
K=L-6

K+L = 16
K-L = -6

Row 2 - Row 1 → Row 2
K+L = 16
-2L = -22


L = -22/-2 = 11
K = 16-L = 16-11 = 5

K = 5
L = 11

Our linear equations calculator calculates it.

x+y=16
x=3y

x+y=16
x=3·y

x+y = 16
x-3y = 0

Row 2 - Row 1 → Row 2
x+y = 16
-4y = -16


y = -16/-4 = 4
x = 16-y = 16-4 = 12

x = 12
y = 4

Our linear equations calculator calculates it.



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