Cross five

The figure on the picture is composed of the same squares and has a content of 45cm². What's its perimeter?

Result

o =  36 cm

Solution:

$S=45 \ \text{cm}^2 \ \\ S_{1}=S/5=45/5=9 \ \text{cm}^2 \ \\ \ \\ S_{1}=a^2 \ \\ a=\sqrt{ S_{1} }=\sqrt{ 9 }=3 \ \text{cm} \ \\ \ \\ o=4 \cdot \ 3 \cdot \ a=4 \cdot \ 3 \cdot \ 3=36 \ \text{cm}$

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