Trapezoid - hard example

Base of the trapezoid are: 24, 16 cm.
Diagonal 22, 26 cm.
Calculate its area and perimeter.

Correct result:

S =  264 cm2
o =  67.966 cm

Solution:

a=24 cm c=16 cm  u=22 cm v=26 cm  w=a+c=24+16=40 cm  s=u+v+w2=22+26+402=44 cm  S=s (sw) (su) (sv)=44 (4440) (4422) (4426)=264 cm2

Try calculation via our triangle calculator.

S=a+c2 h=w2 h  h=2 S/w=2 264/40=665=13.2 cm  u2=h2+a12=13.22+17.62=435625=174.24  a1=u2h2=22213.22=885=17.6 cm a2=aa1=2417.6=325=6.4 cm  b2=h2+a22  b=h2+a22=13.22+6.4214.6697 cm  c1=v2h2=26213.22=1125=22.4 cm c2=ac1=2422.4=85=1.6 cm  d2=h2+c22  d=h2+c22=13.22+1.6213.2966 cm   o=a+b+c+d=24+14.6697+16+13.2966=67.966 cmS=\dfrac{ a+c }{ 2 } \cdot \ h=\dfrac{ w }{ 2 } \cdot \ h \ \\ \ \\ h=2 \cdot \ S/w=2 \cdot \ 264/40=\dfrac{ 66 }{ 5 }=13.2 \ \text{cm} \ \\ \ \\ u^2=h^2 +a_{1}^2=13.2^2 +17.6^2=\dfrac{ 4356 }{ 25 }=174.24 \ \\ \ \\ a_{1}=\sqrt{ u^2 - h^2 }=\sqrt{ 22^2 - 13.2^2 }=\dfrac{ 88 }{ 5 }=17.6 \ \text{cm} \ \\ a_{2}=a - a_{1}=24 - 17.6=\dfrac{ 32 }{ 5 }=6.4 \ \text{cm} \ \\ \ \\ b^2=h^2 + a_{2}^2 \ \\ \ \\ b=\sqrt{ h^2 + a_{2}^2 }=\sqrt{ 13.2^2 + 6.4^2 } \doteq 14.6697 \ \text{cm} \ \\ \ \\ c_{1}=\sqrt{ v^2 - h^2 }=\sqrt{ 26^2 - 13.2^2 }=\dfrac{ 112 }{ 5 }=22.4 \ \text{cm} \ \\ c_{2}=a - c_{1}=24 - 22.4=\dfrac{ 8 }{ 5 }=1.6 \ \text{cm} \ \\ \ \\ d^2=h^2 + c_{2}^2 \ \\ \ \\ d=\sqrt{ h^2 + c_{2}^2 }=\sqrt{ 13.2^2 + 1.6^2 } \doteq 13.2966 \ \text{cm} \ \\ \ \\ \ \\ o=a+b+c+d=24+14.6697+16+13.2966=67.966 \ \text{cm}



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