Two chords

In a circle with radius r = 26 cm two parallel chords are drawn. One chord has a length t1 = 48 cm and the second has a length t2 = 20 cm, with the center lying between them. Calculate the distance of two chords.

Correct result:

v1 =  34 cm
v2 =  14 cm

Solution:

r=26 cm t1=48 cm t2=20 cm  x1=r2(t1/2)2=262(48/2)2=10 cm x2=r2(t2/2)2=262(20/2)2=24 cm  v1=x2+x1=24+10=34 cm
v2=x2x1=2410=14 cm



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