Widescreen monitor

Computer business hit by a wave of widescreen monitors and televisions. Calculate the area of ​​the LCD monitor with a diagonal size 20 inches at ratio 4:3 and then 16:9 aspect ratio.

Is buying widescreen monitors with same diagonal more advantageous than buying 4:3 monitor?

Result

S1 =  1238.707 cm2
S2 =  1102.707 cm2

Solution:

1 inch2=(2.54 cm)2=6.4516 cm2 k1=2.542=6.4516 u=20 inch b1=u/(4/3)2+1=20/(4/3)2+1=12 a1=4/3 b1=4/3 12=16 S1=a1 b1 k1=16 12 6.4516=1238.7072=1238.707 cm21 \ inch^2 = (2.54 \ cm)^2 = 6.4516 \ cm^2 \ \\ k_{ 1 } = 2.54^{ 2 } = 6.4516 \ \\ u = 20 \ inch \ \\ b_{ 1 } = u / \sqrt{ (4/3)^{ 2 }+1 } = 20 / \sqrt{ (4/3)^{ 2 }+1 } = 12 \ \\ a_{ 1 } = 4/3 \cdot \ b_{ 1 } = 4/3 \cdot \ 12 = 16 \ \\ S_{ 1 } = a_{ 1 } \cdot \ b_{ 1 } \cdot \ k_{ 1 } = 16 \cdot \ 12 \cdot \ 6.4516 = 1238.7072 = 1238.707 \ cm^2
b2=u/(16/9)2+1=20/(16/9)2+19.8052 a2=16/9 b2=16/9 9.805217.4315 S2=a2 b2 k1=17.4315 9.8052 6.45161102.7067=1102.707 cm2 S2<S1b_{ 2 } = u / \sqrt{ (16/9)^{ 2 }+1 } = 20 / \sqrt{ (16/9)^{ 2 }+1 } \doteq 9.8052 \ \\ a_{ 2 } = 16/9 \cdot \ b_{ 2 } = 16/9 \cdot \ 9.8052 \doteq 17.4315 \ \\ S_{ 2 } = a_{ 2 } \cdot \ b_{ 2 } \cdot \ k_{ 1 } = 17.4315 \cdot \ 9.8052 \cdot \ 6.4516 \doteq 1102.7067= 1102.707 \ cm^2 \ \\ S_{ 2 }<S_{ 1 }







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Pythagorean theorem is the base for the right triangle calculator. Do you want to convert area units? See also our trigonometric triangle calculator.

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