# Widescreen monitor

Computer business hit by a wave of widescreen monitors and televisions. Calculate the area of ​​the LCD monitor with a diagonal size 20 inches at ratio 4:3 and then 16:9 aspect ratio.

Result

S1 =  1238.707 cm2
S2 =  1102.707 cm2

#### Solution:

$1 \ inch^2 = (2.54 \ cm)^2 = 6.4516 \ cm^2 \ \\ k_{ 1 } = 2.54^{ 2 } = 6.4516 \ \\ u = 20 \ inch \ \\ b_{ 1 } = u / \sqrt{ (4/3)^{ 2 }+1 } = 20 / \sqrt{ (4/3)^{ 2 }+1 } = 12 \ \\ a_{ 1 } = 4/3 \cdot \ b_{ 1 } = 4/3 \cdot \ 12 = 16 \ \\ S_{ 1 } = a_{ 1 } \cdot \ b_{ 1 } \cdot \ k_{ 1 } = 16 \cdot \ 12 \cdot \ 6.4516 = 1238.7072 = 1238.707 \ cm^2$
$b_{ 2 } = u / \sqrt{ (16/9)^{ 2 }+1 } = 20 / \sqrt{ (16/9)^{ 2 }+1 } \doteq 9.8052 \ \\ a_{ 2 } = 16/9 \cdot \ b_{ 2 } = 16/9 \cdot \ 9.8052 \doteq 17.4315 \ \\ S_{ 2 } = a_{ 2 } \cdot \ b_{ 2 } \cdot \ k_{ 1 } = 17.4315 \cdot \ 9.8052 \cdot \ 6.4516 \doteq 1102.7067= 1102.707 \ cm^2 \ \\ S_{ 2 } Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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