# Nine-gon

Calculate the perimeter of a regular nonagon (9-gon) inscribed in a circle with a radius 13 cm.

Result

x =  80.03 cm

#### Solution:

$\theta = \dfrac{ 180^\circ }{ 9} = \dfrac{ \pi}{ 9} = 20 ^\circ \ \\ a = 2r \sin( \dfrac{ \pi}{ 9} ) = 8.89 \ cm \ \\ x = 9a = 80.03 \ \text { cm }$

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