Chord BC

A circle k has the center at the point S = [0; 0]. Point A = [40; 30] lies on the circle k. How long is the chord BC if the center P of this chord has the coordinates [- 14; 0]?

Correct answer:

x =  96

Step-by-step explanation:

r=(400)2+(300)2=50 x0=14=14  (x/2)2 +x02 = r2  x=2 r2x02=2 502142=96



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