# Chord BC

A circle k has the center at the point S = [0; 0]. Point A = [40; 30] lies on the circle k. How long is the chord BC if the center P of this chord has the coordinates: [- 14; 0]?

Result

x =  96

#### Solution:

$r=\sqrt{ (40-0)^2+(30-0)^2 }=50 \ \\ x_{0}=|-14|=14 \ \\ \ \\ (x/2)^2 +x_{0}^2=r^2 \ \\ \ \\ x=2 \cdot \ \sqrt{ r^2-x_{0}^2 }=2 \cdot \ \sqrt{ 50^2-14^2 }=96$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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