# Arm-leg

Calculate the length of the base of an isosceles triangle with a circumference 224 cm if the arm length is 68 cm.

Correct result:

x =  88 cm

#### Solution:

$o=224 \ \text{cm} \ \\ r=68 \ \text{cm} \ \\ \ \\ o=x + 2r \ \\ \ \\ x=o - 2 \cdot \ r=224 - 2 \cdot \ 68=88 \ \text{cm}$

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