Arm-leg

Calculate the length of the base of an isosceles triangle with a circumference 224 cm if the arm length is 68 cm.

Correct result:

x =  88 cm

Solution:

o=224 cm r=68 cm  o=x+2r  x=o2 r=2242 68=88 cmo=224 \ \text{cm} \ \\ r=68 \ \text{cm} \ \\ \ \\ o=x + 2r \ \\ \ \\ x=o - 2 \cdot \ r=224 - 2 \cdot \ 68=88 \ \text{cm}

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