Circular pool

The base of the pool is a circle with a radius r = 10 m, excluding a circular segment that determines the chord length 10 meters. The pool depth is h = 2m. How many hectoliters of water can fit into the pool?

Correct result:

x =  6102 hl

Solution:

r=10 m t=10 m h=2 m a=t/2=10/2=5 m  α=2 arcsin(ar)=2 arcsin(510)1.0472 rad α2=α  =α 180π   =1.0471975511966 180π   =60    S1=π r2 2πα2π=3.1416 102 2 3.14161.04722 3.1416261.7994 m2  b=r2a2=10252=5 3 m8.6603 m  S2=a b2=5 8.6603221.6506 m2  S=S1+2 S2=261.7994+2 21.6506305.1007 m2  V=h S=2 305.1007610.2013 m3  x=V hl=V 10  hl=610.20131597674 10  hl=6102 hl



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