Tetrahedral prism

The height of a regular tetrahedral prism is three times greater than the length of the base edge. Calculate the length of the base edge, if you know that the prism volume is 2187 cm³.

Result

a =  9 cm

Solution:

$a^2 h = 2187 \ \\ a^2 3a = 2187 \ \\ a^3 = 729 \ \\ a = \sqrt[3]{729} = 9 \ \text { cm } \ \\$

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