# Parallelogram

In the parallelogram we know one internal angle 67°33`. Calculate the other internal angles.

Correct result:

β =  112.45 °
γ =  67.55 °
δ =  112.45 °

#### Solution:

$\beta =180-\left(67+33\mathrm{/}60\right)={\frac{2249}{20}}^{\circ }=112.4{5}^{\circ }=11{2}^{\circ }2{7}^{\mathrm{\prime }}$
$\gamma =67+33\mathrm{/}60={\frac{1351}{20}}^{\circ }=67.5{5}^{\circ }=6{7}^{\circ }3{3}^{\mathrm{\prime }}$
$\delta =180-\left(67+33\mathrm{/}60\right)={\frac{2249}{20}}^{\circ }=112.4{5}^{\circ }=11{2}^{\circ }2{7}^{\mathrm{\prime }}$

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