# MO - triangles

On the AB and AC sides of the triangle ABC lies successive points E and F, on segment EF lie point D. The EF and BC lines are parallel and is true this ratio FD:DE = AE:EB = 2:1. The area of ABC triangle is 27 hectares and line segments EF, AD, and DB segments are divided into four parts. Find the areas of these four parts.

Result

AED =  4 ha
BDE =  2 ha
BCFD =  13 ha

#### Solution:

$AED=4 = 4 \ \text { ha }$
$ADF=8 = 8 \ \text { ha }$
$BDE=2 = 2 \ \text { ha }$
$BCFD=13 = 13 \ \text { ha }$

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